Calculate the momentum of the electron if it is moving with 1/3rd of t

1.	Calculate the momentum of the electron if it is moving with 1/3rd of the velocity of light.
Answer» Solution :Mass of the moving electron `(m') = (m_("rest"))/(SQRT(1 - ((v)/(c))^(2))` Putting `v = (c)/(3)` `m' = (m)/(sqrt(1 ((c)/(3c))^(2))) = (m)/(sqrt(1 - ((1)/(3))^(2))) = (3m)/(sqrt8)` Momentum `= m'v = (3m)/(sqrt8) xx (c)/(3) =(mc)/(sqrt8) = ((9.11 xx 10^(-31)kg) (3 xx 10^(10) ms^(-1)))/(2.828) = 9.66 xx 10^(-21) kg m s^(-1)`

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