1.

Calculate the no.of moles in 0.008g of phosphorus

Answer» HI mate.

Thanks for asking this question.

Here is your answer,


GIVEN :

W = 0.008g.

M = P

= 30.

We know that,


For CALCULATING the no. of MOLES.




n = \frac{w}{m}


n \: = \: \frac{8 \times {10}^{ - 3} }{30}

n \: = \frac{4 \times {10}^{ - 3} }{15}

n \: = \: 0.266 \times {10}^{ - 3}


n \: = \: 2.6 \times {10}^{ - 4}


Thank you.



BE BRAINLY !!!!!!!!


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