Saved Bookmarks
| 1. |
Calculate the no. of moles of Ethane required to produce 44 g of CO_(2(g)) after combustion . |
|
Answer» Solution :Balanced equation for the combustion of ETHANE ` C_(2) H_(6) +(7)/(2) O_(2) to 2 CO_(2) + 3H_(2)O` `rArr 2C_(2)H_(6) + 7O_(2) to 4CO_(2) + 6H_(2) O` To produce 4 moles of `CO_(2)`, 2moles of ethane is required `:.`To produce 1 MOLE (44g) of `CO_(2)`required NUMBER of moles of ethane ` = (2 "mol ethane")/(4cancel(molCO_(2)))xx 1 cancel(molCO_(2))` ` = (1)/(2)` mole of ethane` 0 . 5 `mole of ethane. |
|