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Calculate the numbe of oxygen atoms present in 120g of nitric acid `(HNO_(3))` |
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Answer» Molar mass of `HNO_(3)==1xx"Atomic mass of H"+1xx"Atomic mass of N"+3xx"Atomic mass of O"` `=1xx1+1xx14xx3xx16=63u` Gram molar mass of `HNO_(3)`=63g `63"g of "HNO_(3) "contains oxygen atoms"=3xx6.022xx10^(3)"atoms"` `120"g of "HNO_(3) "contains oxygen atoms"=3xx6.022xx10^(230)xx((120g))/((63g))` `=3.44xx10^(24)"atoms"` |
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