1.

Calculate the numbe of oxygen atoms present in 120g of nitric acid `(HNO_(3))`

Answer» Molar mass of `HNO_(3)==1xx"Atomic mass of H"+1xx"Atomic mass of N"+3xx"Atomic mass of O"`
`=1xx1+1xx14xx3xx16=63u`
Gram molar mass of `HNO_(3)`=63g
`63"g of "HNO_(3) "contains oxygen atoms"=3xx6.022xx10^(3)"atoms"`
`120"g of "HNO_(3) "contains oxygen atoms"=3xx6.022xx10^(230)xx((120g))/((63g))`
`=3.44xx10^(24)"atoms"`


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