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Calculate the number atoms of oxygen present in 88 g of `CO_(2)` ? What would be the weight of CO having the same number of oxygen atoms ? |
Answer» 44.0 grams of `CO_(2)` contain oxygen atoms `= 2 xx 6.022 xx 10^(23)` atoms 88.0 grams of `CO_(2)` contain oxygen atoms `= 2 xx 2 xx 6.022 xx 10^(23) = 2.41 xx 10^(24)` atoms `6.022 xx 10^(23)` atoms of oxygen are present in `CO = 28.0g` `2.41 xx 10^(24)` atoms of oxygen are present in `CO=(28.0xx2.41xx10^(24))/(6.022xx10^(23))=112.0g`. |
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