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Calculate the number of atoms in a cubic based unit cell having one atome on each corner and two atoms on each body diagonal. |
Answer» It may be noted that there are four body diagonals passing through the centre and connecting opposity corners. The atoms present on these diagonals are not shared by the surrounding unit cells. Contribution by two atoms present on one body diagonal = 2 Contribution by four atoms present on one body diagonal = `2xx4=8` Contribution by the atoms present on corners = 1 Total number of atoms present per unit cell `=8+1=9` |
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