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Calculate the number of atoms of each type that are present in `3.42 g` of sucrose `(C_(12) H_(22) O_(11))`. |
Answer» `Mw` of sucrose `= C_(12) H_(22) O_(11)` `= 12 xx 12 + 1 xx 22 + 16 11` `= 342 g` a. 1 mol of sucrose `= 342 g = 12 mol of C` `:. 3.42 g = (12)/(342) xx 3.42` `= 0.12 mol of C = 0.12 xx 6.023 xx 10^(23) "atoms"` `= 7.228 xx 10^(22) "atoms of" C` b. `342 g` of Sucrose `= 22 mol of H` `3.42 g` of sucrose `= (22)/(342) xx 3.42` `= 0.22 mol of H` `= 0.22 xx 6.023 xx 10^(23) `atoms `=132.5 xx 10^(21)` atom of `H` c. `342 g` of sucrose `= (11 xx 6.023 xx 10^(23))/(342) xx 3.42` `= 66.25 xx 10^(21)` atoms of `O` |
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