Calculate the number of atoms present in 1.4 g of N2 molecule. – InterviewSolution

1.

Calculate the number of atoms present in 1.4 g of N2 molecule.

Answer»

28 g of N₂ molecule contain 2 × 6.023 × 10²³ atoms.

Hence, 1.4 g of N₂ molecules contain

\(\frac{2\times6.023\times10^{23}}{28}\) = 1.04 = 6.023 x 10²² atoms.

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