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Calculate the number of atoms present in 1.4 of N2 MOLECULE |
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Answer» And then finding no of molecule multiply by 2 As Na×2×0.05That is answer Mole = total molecular weight/ ome molecular weightSo n = 1.4÷28 = o.05THEN no of N2 MOLECULE = .05×Na Na = 6.023×10 power 23 In 28g = 6.022 ×10 ki power 23 moleculesIn 1g =avogadro no. ÷ 28In 1.4 g= avogadro no. ÷ 28 ×1.4 moleculesNow multiply the answer with 2 |
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