1.

Calculate the number of atoms present in 1 Kg of gold.

Answer»

The atomic mass of Gold = 197 g mol-1

197 g of gold contains 6.023 x 1023 atoms of gold. 

∴ 1000 g of gold will contain = \(\frac{1000\times6.023\times10^{23}}{197}\) = 3.055 x 1024 atoms of Gold.



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