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Calculate the number of atoms present in 5.6 litres of a (i) monoatomic, and (ii) diatomic gas at NTP. |
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Answer» Solution :No. of MOLES of the GAS at NTP = `5.6/(22.4) = 1/4` `therefore` no. Of MOLECULES of the gas `=1/4 xx 6.022 xx 10^(23)` `=1.5 xx 10^(23)` no. of molecules of the gas `=1/4 xx 6.022 xx 10^(23)` `=1.5 xx 10^(23)` Now, if the gas is monoatomic, the no. of atoms of the gas = no. of molecules `=1.5 xx 10^(23)` And if the gas is diatomic, no. of atoms `=2 xx` no. of molecules `=2 xx 1.5xx 10^(23)` `=3.0 xx 10^(23)` |
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