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Calculate the number of bond pairs and lone pairs in Icl_(4)^(-). |
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Answer» Solution :No. of valence ELECTRONS in `I = 7` Out of 7,4 electrons are bonded to four `Cl^(-)` ATOMS. ` :. ` It has 4- bond pairs No. of LONE pairs = Valence electrons - Bond pairs ` = 7 - 4 = 3` No. of lone pair ` = 3 + 1` (charge on Cl) = 4 electrons or 2 lone pairs |
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