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Calculate the number of conductors on each pole piece required in a compensating winding for a 6-pole lap-wound dc armature containing 286 conductors. The compensating winding carries full armature current. Assume ratio of pole arc/ pole pitch = 0.7.(a) 6(b) 8(c) 9(d) 7I had been asked this question by my college professor while I was bunking the class.Question is taken from Ways to Reduce Effects of Armature Reaction topic in section Armature Reaction of DC Machines

Answer»

Right answer is (a) 6

The EXPLANATION: The NUMBER of ampere-turns required for compensating winding is ATcw /pole = ATa (peak) *(pole arc/pole pitch) = [IaZ/(AP2)] * (pole arc/pole pitch).

Ncw/pole = (Z/2AP) * (pole arc/pole pitch) = [286 / (2*6*6)] 0.7 = 2.78.

Compensating conductors/pole = 2 * 2.78 = 6 (nearest integer).



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