Calculate the number of electrons lost in the following change : Fe +

1.	Calculate the number of electrons lost in the following change : Fe + H_(2)O rarr Fe_(3)O_(4)+H_2
Answer» SOLUTION :`3Fe^(0)+8erarr(FE^(+3///2))` `([(H^(+))_(2)rarr(H^(0))_(2)+2E]xx4)/(3Fe+4H_(2)OrarrFe_(3)O_(4)+4H_2)` `:.` Lost electron = 8

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