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Calculate the number of gram molecules contained in the following masses. (i) 4.4 g of CO_(2) (ii) 36.0 g of H_(2)O (iii) 0.098 g of H_(2)SO_(4) |
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Answer» Solution :(i) The MOLECULAR mass of `CO_(2)` `=12.01 + (2 xx 16.0) = 44.0 amu` `THEREFORE` No. of gram molecules in 4.4 g of `CO_(2) = 4.4/(44.0) = 0.1` (II) The molecular mass of `H_(2) O = (2 xx 1.008) + 16.0 = 18.016` amu Therefore, the NUMBER of gram molecules present in 36.0 g of `H_(2)O = (36.0)/(18.016) = 2.0` (iii) The molecular mass of `H_(2)SO_(4)` `=(2 xx 1.008) + 32.0 + (4 xx 16.0) = 98.016` amu Hence, the number of gram molecules present in 0.098 g of `H_(2)SO_(4) = 0.098/(98.016)= 1.0 xx 10^(-3)` |
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