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Calculate the number of `H` atoms in `39.6g` of ammonium sulphate, `(NH_(4))_(2) SO_(4)`.A. `4.41xx10^(24) H` atomsB. `7.86xx10^(24) H` atomsC. `1.44xx10^(24) H` atomsD. `5.72xx10^(24) H` atoms |
Answer» Correct Answer - C `underset(underset("sulphate")("ammonium"))("Mass of")rarr underset(underset("sulphate")("ammonium"))("Moles of")rarr underset(underset("sulphate")("of ammonium"))("Formula units")rarr underset(underset("atoms")("of H"))("Number")` `36.6g(NH_(4))_(2)SO_(4)xx(1"mol"(NH_(4))_(2)SO_(4))/(132.1g(NH_(4))_(2)SO_(4))` `xx(6.022xx10^(23)"formula units")/(1 "mol"(NH_(4))_(2)SO_(4))xx("8 H atoms")/("1 formula unit")` `=1.44xx10^(24)` H atoms |
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