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Calculate the number of `kJ` of heat necessary to raise the temperature of `60.0 g` of aluminium from `35^(@)C` to `55^(@)C`. Molar heat capacity of `Al` is `24 J g m^(-1)`. |
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Answer» `q=nxxCxxDeltaT=(60/27 mol)(24 J mol^(-1)K^(-1))(55-35K)` `=1066.7 J=1.07 kJ` |
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