1.

Calculate the number of molecules in a drop of water weighing 0.05 g.

Answer»


Solution :18.0 G of `H_(2)O` CONTAIN molecules `= 6.022 xx 10^(23)`
0.05 g of `H_(2)O` contain molecules `= (0.05)/(18.0)xx6.022xx10^(23)=1.672xx10^(21)` molecules.


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