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Calculate the number of molecules of `SO_(2)` present in 44g of it. |
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Answer» Gram molecular mass of `SO_(2)=32xx2xx16=64g` `64"g of "SO_(2)"have molecules"=N_(A)=6.022xx10^(23)` `44"g of "SO_(2)"have molecules"=((6.022xx10^(23)))/((64g))xx(44g3.76xx10^(23))` |
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