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Calculate the number of molecules present in one drop of `H_(2) O` whose mass is `0.01 g` b. Calculate the number of molecules leaving the liquid suface per second, if the same drop of water evaporates in one hour. |
Answer» a. `0.01 g of H_(2) O = (0.01)/(18) mol` `= (0.01)/(18) xx 6.022 xx 10^(23)` molecules b. Number of moleucles leaving per second `= (3.345 xx 10^(20))/(60 x 60) = 9.293 xx 10^(16)` molecules |
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