1.

Calculate the number of moles of hydrogen:P1V1T2 = P2V2T1P1 = 5 atmP2 = 800 torrT1 = 70°FT2 = ?V1 = 300mLV2 = 5L

Answer»

Given , P1 = 5 atm

P2 = 800 torr

T1 = 70° F

T2 = ?

V1 = 300 mL

V2 = 5L

\(\because\) 760 torr = 1 atm

\(\therefore\) 800 torr = 800/700 = 8/7 atm

using ideal gas equation

\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\) 

⇒ \(\frac{5\times300}{70}\) = \(\frac{8/7\times5000}{T_2}\) 

⇒ T\(\frac{8\times5000\times70}{7\times5\times300}\)

T2  = 266.67°

or T2 = 403.52 k

Therefore, number of mole of hydrogen gas = \(\frac{P_2V_2}{T_2R}\) 

\(\frac{8/7\times5}{403.52\times0.082}\) = 0.173 mole



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