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Calculate the number of moles of hydrogen:P1V1T2 = P2V2T1P1 = 5 atmP2 = 800 torrT1 = 70°FT2 = ?V1 = 300mLV2 = 5L |
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Answer» Given , P1 = 5 atm P2 = 800 torr T1 = 70° F T2 = ? V1 = 300 mL V2 = 5L \(\because\) 760 torr = 1 atm \(\therefore\) 800 torr = 800/700 = 8/7 atm using ideal gas equation \(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\) ⇒ \(\frac{5\times300}{70}\) = \(\frac{8/7\times5000}{T_2}\) ⇒ T2 = \(\frac{8\times5000\times70}{7\times5\times300}\) T2 = 266.67° or T2 = 403.52 k Therefore, number of mole of hydrogen gas = \(\frac{P_2V_2}{T_2R}\) \(\frac{8/7\times5}{403.52\times0.082}\) = 0.173 mole |
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