calculate the number of molesand molecules present in0.032mg of methan

1.	calculate the number of molesand molecules present in0.032mg of methane
Answer» moles = mass / molar mass mass methane = 0.032 mg = 3.2x10^-5 g moles methane = 3.2x10^-5 g / 16.042 g/mol = 1.994x10^-6 moles methane = 2.0x10^-6 moles 1 mole of anything is 6.022x10^23 units of that anything. So 1 mole metane has 6.022x10^23 molecules of methane. Thus molecules of methane = moles x 6.022x10^23 molecules / mol = 1.994x10^-6 mol x 6.022x10^23 molecules/mol = 1.2x10^18 molecules

calculate the number of molesand molecules present in0.032mg of methane

Answer»

moles = mass / molar mass

mass methane = 0.032 mg = 3.2x10^-5 g

moles methane = 3.2x10^-5 g / 16.042 g/mol

= 1.994x10^-6 moles methane

= 2.0x10^-6 moles

1 mole of anything is 6.022x10^23 units of that anything.

So 1 mole metane has 6.022x10^23 molecules of methane.

Thus molecules of methane = moles x 6.022x10^23 molecules / mol

= 1.994x10^-6 mol x 6.022x10^23 molecules/mol

= 1.2x10^18 molecules