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calculate the number of Na ions and SO4 ions present in 7.2 g of Na2SO4 a)6*10^23&3*10^23 b)6*10^22&3*10^22 c)3*10^23&6*10^23 d)6*10^24&3*10^24 |
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Answer» Answer: Explanation: MOLES of Na2SO4 = 7.2/142 = 0.05 0.05 mole contain = 2 * 0.05*6.022*10^23 = 6.022 * 10^22 OD Na and 0.05*6.022*10^23 = 3.011*10^22 mole of SO2 option B |
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