1.

Calculate the number of oxalic acid molecules in 100 mL of 0.02 N oxalic acid solution.

Answer»


Solution :Molarity`=(0.02)/(2)=0.01 M`
No of molecules in ONE MOLAR solution `=6.02xx10^(23)`
No. of molecules in 100 mL of 0.01 M oxalic acid solution
`=(0.01xx6.02xx10^(23))/(1000)xx100=6.02xx10^(20)`


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