Calculate the number of oxalic acid molecules in `100 mL` of `0.02 N` oxalic acidA. (a)`6.023xx10^(20)`B. (b)`6.023xx10^(21)`C. (c )`6.023xx10^(22)`D. (d)`6.023xx10^(23)`

Calculate the number of oxalic acid molecules in `100 mL` of `0.02 N`

1.	Calculate the number of oxalic acid molecules in `100 mL` of `0.02 N` oxalic acidA. (a)`6.023xx10^(20)`B. (b)`6.023xx10^(21)`C. (c )`6.023xx10^(22)`D. (d)`6.023xx10^(23)`
Answer» Correct Answer - a Normality = Molarity`xx` Valence factor `:.` Molarity`="Narmality"/("Valence factor")` Valence factor for oxalic acid `=("mo. Wt. of oxalic acid")/("Eq. wt. of oxalic acid")` `=("mo. Wt. of oxalic acid")/("mo. Wt. of oxalic acid")xx 2` (As basically of oxalic acid is) `"Molarity"=20/2=0.01` Number of millimoles `=0.01xx100` Number of moles=`0.001` `:.` Number of oxalic acid molecules`=0.001xx6.023xx10^(23) = 6.023xx10^(20)`

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Calculate the number of oxalic acid molecules in `100 mL` of `0.02 N` oxalic acidA. (a)`6.023xx10^(20)`B. (b)`6.023xx10^(21)`C. (c )`6.023xx10^(22)`D. (d)`6.023xx10^(23)`

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