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Calculate the number of protons , electrons and neutrons in the following. (a) Chloride ion `(Cl^(-))` with `Z = 17,A =35` (b) Aluminium ions`(Al^(3+)) ` with `Z = 13 , A=27` |
Answer» (a)`Cl^(-) ` with `Z = 17 , A= 35` Number of protons`= 17` Number of electrons `=17 +1` ( As one negative charge which means gains of electron) `=18` Number of neutrons `= A-Z = 35 - 17 = 18` ( b) `Al^(3+)` with `Z= 13 ` `A=27` Number of protons `= 13` Number of electrons `=13-3 = 10 ` ( As it has three positive charge obtained by the loss of three electrons) number of neutrons `= A-Z= 27-13=14` |
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