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Calculate the number of sulphate ions in 100 mL of 0.001 M H_(2)SO_(4)solution. |
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Answer» SOLUTION :No. Of moles = molarity `XX` volume in litres `=0.001 xx 0.1 = 0.0001` Now, 1 molecules of `H_(2)SO_(4)` contains 1 `SO_(4)^(2-)` ion. `therefore` 1 mole of `H_(2)SO_(4)` contains 1 mole of `SO_(4)^(2-)` `therefore 0.0001` mole of `H_(2)SO_(4)` contains 0.0001 mole of `SO_(4)^(2-)` `therefore` NUMBER of sulphate ions = moles of ions `xx` AV. const. `=0.0001 xx 6.022 xx 10^(23) = 6.022 xx 10^(19)` |
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