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Calculate the numberof rigns present in C_(18)H_(12) |
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Answer» Solution :DOUBLE bondequivalentformula `=(C-(H)/(2)+ (N )/(2) +1)` When`C= no`of carbonatoms H= noof HYDROGENAND halogenatomsand N= no .ofnitrogenatoms So in `C_(18) H_(12)` Doublebondequivalent `=18 (12)/(2)+ 0 + 1 -=18 -6+1=13`  Oneringis equalto onedoublebondequivalent. : Hencefourringsare therefourboubleequivalentare usedsoremaining13-4=9ninedoublebonsare presentin thering hence`C_(18) H_(12)` containfouraromaticrings . |
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