Calculate the [OH^(-)] of a solution whose pH is 9.62.

1.	Calculate the [OH^(-)] of a solution whose pH is 9.62.
Answer» Solution :`pH+pOH=14, pOH=14-pH=14.9.62=4.38` `pOH=4.38=-log_(10)[OH^(-)],4.38=-log_(10)[OH^(-)]` `log_(10)[OH^(-)]=-4.38, [OH^(-)]=` antiolog `(-4.38)=` antilog `(5-4.38-5)` `=` antilog `(0.62-5)=`antilog `(0.62)xx10^(-5)=4.269xx10^(-5)"mol"dm^(-3)`

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