1.

Calculate the osmotic pressure of a solution obtained by mixing 100 cm of 3.4% aqueous solution ofurea (NH,CONH,) and 100 cm' of 1.6% aqueous solution of sugar C12H22011 at 20°C.

Answer»

Urea and cane sugar are very dissolvable in water. But we assume these molecules cannot pass through a semipermeable membrane. Only water can pass through.

π = Osmotic pressure = C_solute * R T

R = 8.314 J/°K C_solutes = Molar concentration of solutes

T = absolute temperature = 293°K given

We assume that the volume of Urea and Cane sugar in the solutions are negligible as the concentrations are low.

Molar concentration: in 200 ml we have

Solutes = 3.4 / 60 moles of Urea + 1.6 /342 moles of cane sugar = 0.061 moles = 0.061 * 1000ml /200 ml = 0.306 M

Since Cane sugar and Urea are not Ionic, we do not multiply the concentration by any factor.

Osmotic pressure =π = 0.306 * 8.314 * 293 = 745 Pa



Discussion

No Comment Found