1.

Calculate the oxidation number of Chromium in CrO_(5) . Suggest structure of this compound. Count for the fallacy.

Answer»

Solution :`(x)+[(-2)xx5]=0`
or x=+10
The O.N. of +10 for Cr is not POSSIBLE because the maximum O.S. of Cr is +6 (outer electronic config: `3d^(5)4s^(1)` ). The fallacy is removed if we consider the following structure for `CrO_(5)`.

On the BASIS of above structure, we have
`[(-1)xx4]+(x)+(-2)=0`
or `-4+x-2=0`
or x=+6


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