Calculate the oxidation number of (i) Fe in Fe_3O_4 (ii) S in Na_2S_4O_6 (iii) Pb in Pb_3O_4 (iv) Nin (NH_4)_2SO_4.

Calculate the oxidation number of (i) Fe in Fe_3O_4 (ii) S in Na_2S_4O

1.	Calculate the oxidation number of (i) Fe in Fe_3O_4 (ii) S in Na_2S_4O_6 (iii) Pb in Pb_3O_4 (iv) Nin (NH_4)_2SO_4.
Answer» Solution :(i) FE in `Fe_3O_4`. LET the oxidation number of Fe be X. `{:(x,-2,3x-8=0),(Fe_3,O_4,3x=8),(("x"xx3),(-2xx4),x=8//3=2.67):}` (ii) S in `Na_2S_4O_6` . Let the oxidation number of S be x. `{:(+1,x,-2,2+4x-12=0),(Na_2,S_4,O_6,""4x=10),(("x" xx3),("x" xx4),(-2xx6),""x=10/4=2.5):}` (iii) Pb in `Pb_3O_4` . Let the oxidation no. of Pb be x. `{:(x,-2,,3x-8=0),(Pb_3,O_4,,3x=8),(("x" xx3),(-2xx4),"or",x=8/3=2.67):}` (iv)N in `(NH_4)_2SO_4` . Let the oxidation no. of N be x. `(overset(x)Noverset(+1)H_4) SO_4^(2-)""2x+2(+1xx4)+(-2)=0` `:. ""2x+6=0` `""2x=-6" or"x=-6/2=-3`