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Calculate the oxidation number of Ni in `K_(2)[Ni(CN)_(4)]` . |
Answer» Let the charge on Ni be x Charge on `CN^( ᶱ)=-1` `K_(2)[Ni(CN)_(4)]rarr2K^(o+)+[Ni(CN)_(4)]^(2-)` Charge on complex ion , `[Ni (CN)_(4))_(4)]^(2) = -2` `implies x + 4 x (-1) = -2` `implies x = +2` Oxidation number of Ni is II . |
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