1.

Calculate the oxidation number of Ni ion `[Ni (H_(2)O_(6))_(6)]^(2+)]` .

Answer» Oxidation number is calculated as follows
Charge on complex ino` = +2`
Let charge on `Ni =x`
Charge on `H_(2)O=O`
`implies x + 6 xx (0) = + 2`
`implies x = 2+`
Hence oxidation number of `Ni is II .


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