Calculate the oxidation number of nitrogen in NO_(3)^(-). Suggest structure of this compound. Count for the fallacy.

Calculate the oxidation number of nitrogen in NO_(3)^(-). Suggest stru

1.	Calculate the oxidation number of nitrogen in NO_(3)^(-). Suggest structure of this compound. Count for the fallacy.
Answer» Solution :`(x)+[(-2)xx3]=-1` (as `NO_(3)^(-)` bears a charge of -1). or x=+5 The structure of `NO_(3)` is as follows. On the BASIS of above structure, we have `[(-2)xx2]+(x)+(-1)=0` or x=+5 THUS, this structure GIVES the same O.N. for N in `NO_(3)^(-)`. HENCE, there is no fallacy.