Calculate the oxidation number of Sulphur in H_(2)SO_(5). Suggest structure of this compounds. Count for the fallacy.

Calculate the oxidation number of Sulphur in H_(2)SO_(5). Suggest stru

1.	Calculate the oxidation number of Sulphur in H_(2)SO_(5). Suggest structure of this compounds. Count for the fallacy.
Answer» SOLUTION :`+(1)xx2+(x)+[(-2)xx5]=0` or `x=10-2=8`. The O.N. of +8 for S is not POSSIBLE because it has only 6 electrons in its valence shell and can EXHIBIT a maximum O.S. = + 6. Hence, in `H_(2)SO_(5)`, two oxygen atoms must be linked TOGETHER. This consideration can remove the fallacy. Thus, the structure of `H_(2)SO_(5)` should be as given below. `overset(+1)H-overset(-1)O-underset(-2)underset(O)underset(\|\|)overset(-2)overset(O)overset(\|\|)S-overset(-1)O-overset(-1)O-overset(+1)H` On the basis of the above structure, we have `(+1)+(-2) + XX + [(-2) xx 2] + [(-1) 2] +(+1)=0` or -1 + X-4-2 + 1 = 0 or x=+6.