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Calculate the oxidation number of the underlined atom in the following species. [ul(Co)(NH_(3))_(6)]^(3+) |
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Answer» Solution :`[Co(NH_(3))_(6)]^(3+)` : Let the oxidation number of Co in the GIVEN ion be x. `NH_(3)` is a neutral molecule. Therefore the SUM of oxidation numbers of atoms PRESENT in it is zero. The sum of oxidation numbers of all atoms present in the given ion must be equal to the CHARGE present on it. Therefore, `(x)+(0)xx6=+3` or x=+3 Hence, the oxidation number of Co in `[Co(NH_(3))_(6)]^(3+)` ionis +3. |
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