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Calculate the oxidation number of the underlined element in the following ions. ul(Cr_(2))O_(7)^(2-) |
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Answer» Solution :`Cr_(2)O_(7)^(2-)` : Suppose, the oxidation number of CR in this ion is x. The sum of oxidation NUMBERS of all ATOMS present in this ion must be equal to -2 i.e., the charge present on the ion. Therefore, `(x)xx2+(-2)xx7=-2` or 2x=-2+14=+12 x=+6 Hence, the oxidation number of Cr in `Cr_(2)O_(7)^(2-)` is +6. |
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