1.

Calculate the oxidation number of the underlined element in the following ions. ul(Mn)O_(4)^(2-)

Answer»

Solution :`MnO_(4)^(2-)` : Let the oxidation NUMBER of Mn in this ioni be x.
THEREFORE,
`(x)+(-2)xx4=-2`
or x=-2+8=+6.
HENCE, the oxidation number of Mn in `MnO_(4)^(2-)` ion is +6.


Discussion

No Comment Found