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Calculate the oxidation number of the underlined element in the following molecules. Kul(Mn)O_(4) |
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Answer» Solution :`KMnO_(4)` SUPPOSE the oxidation number of Mn in `KMnO_(4)` is x. The oxidatio number of K is +1 because it is an alkali metal and the oxidation number of each O ATOM is -2. Since `KMnO_(4)` is a neutral molecule, we have `+1+(x)+(-2)xx4=0` or x=+7 HENCE, the oxidation number of Mn in `KMnO_(4)` is +7. |
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