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Calculate the oxidation number of the underlined element in the following molecules. Hul(N)O_(3) |
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Answer» SOLUTION :`HNO_(3)` Let the OXIDATION number of N in `HNO_(3)` be x. The oxidation number of His +1 while that of each oxygen atom is-2. It is a neutral molecule. THEREFORE, we have `+1+(x)+(-2)xx3=0` or x=+5 Hence, the oxidation number of N in `HNO_(3)` is + 5. |
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