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Calculate the oxidation number of the underlined element in the following molecules. K_(2)ul(Cr_(2))O_(7) |
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Answer» Solution :`K_(2)Cr_(2)O_(7)` Suppose the OXIDATION NUMBER of Cr in `K_(2)Cr_(2)O_(7)` is x. The oxidation number of each K atom is +1 while that of O atom is -2. Since K `Cr_(2)O_(7)` is a neutral MOLECULE, we have `(+1)xx2+(x)xx2+(-2)xx7=0` or `2x=+14-2=+12` or x=+6 Hence, the oxidation number of each Cr atom in `K_(2)Cr_(2)O_(7)` is +6. |
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