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Calculate the oxidation number of the underlined element in the following molecules. Na_(2)ul(S_(4))O_(6) |
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Answer» SOLUTION :`Na_(2)S_(4)O_(6)` : Suppose, the OXIDATION number of each S atom in `Na_(2)S_(4)O_(6)` is x. The oxidation number of each Na atom is +1 while that of oxygen atom is -2. Since `Na_(2)S_(4)O_(6)` is a neutral molecule, we have `(+1)xx2+(x)xx4+(-2)xx6=0` or `2+4x-12-2=+10` or `4x=+12-2=+10` or `x=+(10)/(4)=(5)/(2)` HENCE, the oxidation number of each S atom in `Na_(2)S_(4)O_(6)` is `+(5)/(2)` |
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