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Calculate the oxidation number of the underlined element in the following molecules. ul(C)HCl_(3) |
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Answer» Solution :`CHCl_(3)` : Suppose, the oxidation NUMBER of C in `CHCl_(3)` is X. The oxidation number of H is +1 while that of each cl atom is -1 (because Cl is a halogen and is ATTACHED to a less electronegative atom C ). Since `CHCl_(3)` is a neutral molecule, we have `(x)+(+1)XX1+(-1)xx3=0` or x=+2 Hence the oxidation number of C in `CHCl_(3)` is +2. |
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