Saved Bookmarks
| 1. |
Calculate the oxidation number of the underlined element in the following molecules. Na_(3)ul(P)O_(4) |
|
Answer» Solution :`Na_(3)PO_(4)` : SUPPOSE, the oxidation number of P in `Na_(3)PO_(4)` is X. The oxidation number of each NA atom is + 1 while that of each O atom is-2. Since `Na_(3)PO_(4)` is a neutral molecule, we have `(+1)xx3+(x)+(-2)xx4=0` or x=+5 Hence, the oxidation number of P in `Na_(3)PO_(4)` is + 5. |
|