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Calculate the oxidation number of underlined elements in the following.(i) KMnO_(4) (ii) Cr_(2)O_(7)^(2-) |
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Answer» Solution :(i) `KMnO_(4)` 1 (+1) + X + 4(-2) = 0 x-7 =0 x = +7 Oxidation state of Mn = +7. (II) `Cr_(2)O_(7)^(2-)` 2X + 7 (-2) = -2 2x - 14 =-2 2x =+12 `:.` x = +6 Oxidation state of Cr = +6 |
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