Calculate the partial pressures N_2 and H_2 in a mixture of two moles of N_2 and two moles of H_2 at STP.

Calculate the partial pressures N_2 and H_2 in a mixture of two moles

1.	Calculate the partial pressures N_2 and H_2 in a mixture of two moles of N_2 and two moles of H_2 at STP.
Answer» SOLUTION :`p_(N_(2)) = ("number of moles of" H_(2))/(V)xx RT` `p_(H_(2)) = ("number of moles of" H_(2))/(V) = xx RT` MOLE FRACTION of `N_2 = X_(N_(2)) = (2)/(2 +2)` `= (2)/(4) = 0.5` `therefore X_(H_(2)) = 0.5 (X_(N_2) + X_(H_2) = 1.0)` But `P = (RT)/(V)` . For 1 mole `V = 22.4` litres For 4 moles V = `4 xx 22.4 ` litres and `R = 0.821` lit - atm `K^(-1) mol^(-1)` `P = (0.0821 xx 273)/(4 xx 22.4) =0. 2501` atm `p_(N_2) =0.2501 xx 0.5 = 0.1251` atm `p_(H_2) = 0.2501 xx 0.5 = 0.1251 ` atm