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Calculate the percent ionic character of HCL . Given that the observed dipole moment is 1 . 0 3Dand bondlength of HCl is 1 .275 Å. |
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Answer» Solution :If HClwere 100% ionicand would carry charge equal to one unit, VIZ, ` 4.8 xx10^(-10)` esu. As bond LENGTH of HCl is ` 1.275Å` ,its dipole moment for 100% ionic character would be `mu_("ionic") = qxxd = 4.8xx10^(10) esu xx 1.275xx10^(-8) cm = 6 . 12 xx10^(18)` "esu cm "= 6.12 D `mu_("observed")= 1 . 0 3D ("Given")` ` therefore% ` ionic character= `(mu_("observed"))/(mu_("ionic"))xx 100 = (1.03)/(6.12) xx100 = 16.83 %` |
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