Saved Bookmarks
| 1. |
Calculate the percent weight loss suffered by sodium bicarbonate on strong heating? |
|
Answer» Solution :On strong heationg sodium bicarbonate decomposes and loses carbondioxide and water. `2NaHCO_(3) to Na_(2)CO_(3)+H_(2)O+CO_(2)` 2 moles of `NaHCO_)(3)="1 mole of "CO_(2)+"1 mole of "H_(2)O` `(2 xx 84)" grams of "NaHCO_(3)-=(44+18)` gramsweight loss 100 grams of `NaHCO_(3)-=?` The percent weight loss suffered by sodium carbonate on calcination `=(100)/(2 xx 84)xx 62=36.9%` |
|