1.

Calculate the percentage loss of mass when sodium carbone crystals are heated strongly

Answer»

Alculate the percentage composition of each of the elements PRESENT in pure calcium CARBONATE (Ca = 40, C = 12, O = 16).
Solution:
Mass of one mole of pure calcium carbonate (CaCO3)

= Mass of calcium + Mass of CARBON + Mass of OXYGEN
= (40 x 1) + (12 x 1) + (16 x 3)

= 40 + 12 + 48
= 100 g




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